Question

The length of the diagonals of a rhombus are 24cm and 10cm. Find the perimeter.

I already know the answer. I just want someone to answer the question in proper and complete statements.
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Answer 1

Answer:

Here, AC = 24 cm and BD = 10 cm, therefore, AO = 12 cm and BO = 5 cm.

Now to find the perimeter, we need the length of AB.

Let’s find AB using the pythagoras theorem in ABC,

AB2 = AO2 + OB2

AB2 = 122 + 52

AB2 = 144 + 25

AB2 = 169

AB = √169

AB = 13 cm

Since the length of one side of the rhombus is AB = 13cm, perimeter of the rhombus, P = 4 × side of a rhombus

P = 4 × AB

P = 4×13 = 52 cm

Thus, perimeter of the rhombus is 52 cm.

Step-by-step explanation:

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