Question

The length of the diagonals of a rhombus are 24cm and 32 cm.the perimeter of the rhombus is:?

Answer 1

formula is 1/2 * product of its diagonals
 ANSWER wil be - 384cm sq.

Answer 2

Given

length of the diagonals of a rhombus are 24cm and 32 cm.

Find the perimeter of the rhombus .

To proof

Formula

$Perimeter\ of\ rhombus = 2 \sqrt{a^{2}+ b^{2}$

where a , b are the diagonal of the rhombus.

As given

diagonals of a rhombus are 24cm and 32 cm.

put in the above equation

we get

$= 2\sqrt{(24)^{2} + (32)^{2}}$

solve the above

$=2 \sqrt{576 + 1024}$

$=2\sqrt{1600}$

= 2× 40

= 80 cm²

the perimeter of the rhombus is 80 cm².

Hence proved