The length of the diagonals of a rhombus are 30 and 40cm. Find the sides of the rhombus
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An Diagonals of a rhombus are perpendicular bisectors of each other
Suppose the name of the rhombus is ABCD, then AC and BD are it's diagonals which measure 30cm and 40cm respectively and they meet at point O.
so, AO=15cm and BO=20cm
In ∆AOB,
angle AOB=90°
AB2(square)=AO2+BO2
=225+400
=625
AB=25cm
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Answer:
Step-by-step explanation:
let d1=30cm and d2=40cm
using the pythagoras theorem,
s²=(15)²+(20)²
s²=225+400
=625
s=√625
=25
so, each side of rhombus is 25cm
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