the length of the diagonals of a rhombus are in ratio 6:8.if it's perimeter is40cm. find the length of the shorter diagonal.
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let a be the side of the rhombus
so the diagonals will be 8a,6a
perimeter of rhombus =4a
4a =40
a = 40/4
a =10 cm
so the length of diagonals are
8a =8*10 =80cm
6a = 6*10 =60cm
length of shorter diagonal = 60cm
so the diagonals will be 8a,6a
perimeter of rhombus =4a
4a =40
a = 40/4
a =10 cm
so the length of diagonals are
8a =8*10 =80cm
6a = 6*10 =60cm
length of shorter diagonal = 60cm
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