The length of the diagonals of a rhombusis 42 cm and 40 cm.Find the perimeter of the rhombus.
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Let ABCD is a rhombus and AC and BD are its diagonals
=4× sides
Side of rhombus:
=
(
2
AC
)
2
+(
2
BD
)
2
=
(
2
42
)
2
+(
2
40
)
2
=
√441+400
=
29
=29cm
Therefore perimeter =4×sides =4×29= 116 cm
Step-by-step explanation:
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