Question

The length of the diagonals of a rhombusis 42 cm and 40 cm.Find the perimeter of the rhombus.

Answer 1

Answer:

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Answer 2

Answer:

Let ABCD is a rhombus and AC and BD are its diagonals  

=4× sides

Side of rhombus:

=  

(  

2

AC

​  

)  

2

+(  

2

BD

​  

)  

2

 

​  

 

=  

(  

2

42

​  

)  

2

+(  

2

40

​  

)  

2

 

​  

 

=  

√441+400

​  

 

=  

29

​  

 

=29cm

Therefore perimeter =4×sides =4×29= 116 cm

Step-by-step explanation: