The length of the diagonals of a rombhus are 12cm and 16cm. Find the length of the sides
Answers
Answered by
0
Answer:
10 cm
Step-by-step explanation:
In ΔAOD
(AD)
2
=(AO)
2
+(OD)
2
=36+64
AD
2
=100
AD=
100
=10cm
Rhombus has all sides equal
AB = AD = BC = CD = 10 cm
Answered by
0
Step-by-step explanation:
Diagonals of the rhombus cuts each other at 90°.
Since d1 =16and d2 =12
Therefore, by Pythagoras theorem
⇒ a square =( d1/2)square + (d2/2)square
⇒ a square = (16/2)square + (12/2)square
⇒ a square = 8square + 6square
⇒ a square = √100= 10cm
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