Question

the length of the diagonats of a rhombus are 30cm and 40cm.Find the side of the rhombus.​

Answer 1

Answer:

35m

Step-by-step explanation:

2(l+b)

2×70=140

140/4=35m

Answer 2

Given:

A rhombus with -

• Diagonal 1 = 30 cm
• Diagonal 2 = 40 cm

What To Find:

We have to -

• Find the side of the rhombus.

Formula Needed:

The formula is -

$\bf s = \dfrac{\sqrt{(D1)^2 + (D2)^2}}{2}$

Abbreviations Used:

• s = Side
• D1 = Diagonal 1
• D2 = Diagonal 2

Solution:

$\sf \implies s = \dfrac{\sqrt{(D1)^2 + (D2)^2}}{2}$

Substitute the values,

$\sf \implies s = \dfrac{\sqrt{(30)^2 + (40)^2}}{2}$

Find the squares of 30 and 40,

$\sf \implies s = \dfrac{\sqrt{900 + 1600}}{2}$

Add 900 and 1600,

$\sf \implies s = \dfrac{\sqrt{2500}}{2}$

Find the square root of 2500,

$\sf \implies s = \dfrac{50}{2}$

Divide 50 by 2,

$\sf \implies s = 25$

Final Answer:

∴ Thus, the side of the rhombus is 25 cm.