Question

The length of the diameter of the circle x^2+y^2-8x-6y=0 is

Answer 1

Step-by-step explanation:

x 2 +y 2−4x−6y+4=0

x 2 +y 2 +2gx+2fy+c=0

2g=−4⇒g=−2

2f=−6⇒f=−3

c=4

So, the centre of the circle

C=(−g,−f)

C=(2,3)

We know that the radius of circle,

r= √g 2 +f 2 −c

r= √2 2 +3 2 −4

r= √4+9−4

r= 9 =3

So, the diameter of this circle

d=2r=6