Question

the length of the diameter of the circle x²+y²-6x-8y=0

Answer 1

I hope this answer help you

Answer 2

Given:   $x^{2}+y^{2} -6x-8y=0$

We know that the general equation of a circle is of form

$x^{2} +y^{2}+2gx+2fy+c=0$

and the radius of such a circle will be

$\sqrt{g^{2}+f^{2}-c^{2} }$

By comparing the general equation with the given equation, we get

$2g=-6$

$2f=-8$

$c=0$

$Radius=\sqrt{(-3)^{2}+(-4)^{2}-0 }$

            $=\sqrt{9+16}$

            $=\sqrt{25}$

$Radius =5$

$Diameter=5\times 2=10$

So, the diameter of the circle will be $10$

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