the length of the fence of a trapezium - shaped field ABCD is 130m and side AB is perpendicular to each of the parallel side AD and BC =54m, CD =19m and AD =42, find the area of the field
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perimeter of the field.= 130 m
AB+BC+CD+AD=130
AB+54+19+42=130
AB+115=130
AB=130-115
AB=15 m
area of the trapezium =1/2×AD+BC×AB
=1/2×42+54×15
=1/2×96×15
=720 m^2
AB+BC+CD+AD=130
AB+54+19+42=130
AB+115=130
AB=130-115
AB=15 m
area of the trapezium =1/2×AD+BC×AB
=1/2×42+54×15
=1/2×96×15
=720 m^2
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