The length of the fence of a trapezium-shaped field ABCD is 130 m
and side AB is perpendicular to each of the parallel sides AD
and BC. If BC = 54 m, CD = 19 m and AD = 42 m, find the area of
the field.
Answers
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Step-by-step explanation:
The perimeter of field is 130
⟹AB+BC+CD+AD=130
AB=130−54−19−42
AB=15m
Area is given as
2
1
AB(AD+BC)
2
1
×15(54+42)
15×48=720m
2
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