The length of the fence of a trapezium-shaped field ABCD is 300 m. If BC = 96 m, CD = 34 m, and AD = 80 m, find the area of this field. Side AB is perpendicular to parallel sides AD and ВС.
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Answer:
The perimeter of field is 130
⟹AB+BC+CD+AD=130
AB=130−54−19−42
AB=15m
Area is given as
2
1
AB(AD+BC)
2
1
×15(54+42)
15×48=720m
2
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