The length of the fence of a Trapezium shaped field ABCD is a 100m and the side a b is a perpendicular to each of the parallel side a b and b c f b c is 54 CD is 19 m and a b is 42 M find the area of the field
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Length of AB = 54m
Length of AD = 42 m
Length of CD = 19m
Perimeter of trapezium ABCD= 130m
Length of side BC = 130-(54+42+19)
= 130-115 = 15m
Area of the trapezium field = 1/2 X h ( sum of parallel sides )
= 1/2 X AB ( AD + BC )
= 1/2 X 54 ( 42+15)
= 1/2 X 54 X 57
= 1539 m2
Length of AD = 42 m
Length of CD = 19m
Perimeter of trapezium ABCD= 130m
Length of side BC = 130-(54+42+19)
= 130-115 = 15m
Area of the trapezium field = 1/2 X h ( sum of parallel sides )
= 1/2 X AB ( AD + BC )
= 1/2 X 54 ( 42+15)
= 1/2 X 54 X 57
= 1539 m2
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