Math, asked by Ram001kumar, 13 days ago

the length of the fence of a trapezium -shaped field PQRS is 130 m and side PQ is perpendicular to each of the parallel sides PS and QR. If QR = 54 m, RS = 19 m and PS = 42 m, find the area of the field.

Answers

Answered by Dik24
6

Step-by-step explanation:

The perimeter of field is 130

⟹AB+BC+CD+AD=130

AB=130−54−19−42

AB=15m

Area is given as 1/2 AB(AD+BC)

1/2×15(54+42)

15×48=720m square

Attachments:
Answered by XxMissCutiepiexX
34

The perimeter of field is 130

⟹AB+BC+CD+AD=130

AB=130−54−19−42

AB=15m

Area is given as 1/2 AB(AD+BC)

1/2×15(54+42)

15×48=720m square

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