The length of the fenec of trapezium shaped field ABCD is 130 m and side AB is perpendicular to each parallel sides AD and BC. if BC 54 m, CD 19 m and AD 42 m, find the area of the field.
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let side ab be x
130=42+54+19+x
130=115+x
130-115=x
15=x
area of trapezium=sum of parallel sides×height×1/2
=(42+54)×15×1/2
=96×15×1/2
=144×1/2
=72
area of the field is 72m sq
130=42+54+19+x
130=115+x
130-115=x
15=x
area of trapezium=sum of parallel sides×height×1/2
=(42+54)×15×1/2
=96×15×1/2
=144×1/2
=72
area of the field is 72m sq
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