The length of the floor is 32 m longer than its width and there is greater
than 200 square meters. You will cover the floor completely with tiles. What will
be the possible dimension of the floor?
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L , B length & width of floor
floor area = ( w+32)*w =200
w^2 +32w -200 =0
w = -32+ or - sqrt of ( 32 ^2 - 4*1* (-200)) /2
= -32 + or - sqrt of( 1024+800) /2
= -32 + or - sqrt of(1824) /2
= (-32 + or - 42.71) / 2 = 10.71 /2
= 5 .355 m
L = 5 .355 m +32 = 37 .355 m
Dimensions of the floors are L by W = 37 .355 m by 5 .355m
Hope this is helpful for you.
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