Question

the length of the Hour hand of a clock is 4.9 cm find the distance travelled by the tip of the hour and in a week

Answer 1

Length of hour hand r=4.9 cm
Then in a clock each angle between two adjacent 5 min frequency is 30°
(as 12 sets of 5 min then 360°/12⇒30°)

Distance travelled in an hour = length of arc
           Ф/360°×2πr=30°/360°×2×22/7×4.9×4.9
  Solving it             =12.57 cm² (approx)
Then distance travelled in a day=24×12.57
                                                   =301.68 cm² (approx)
So Distance travelled in a week=7×301.68
                                                  =2111.76 cm² (approx)

:) Hope this helps!!!!!!!!!!!!