the length of the Hour hand of a clock is 4.9 cm find the distance travelled by the tip of the hour and in a week
Answers
Answered by
5
Length of hour hand r=4.9 cm
Then in a clock each angle between two adjacent 5 min frequency is 30°
(as 12 sets of 5 min then 360°/12⇒30°)
Distance travelled in an hour = length of arc
Ф/360°×2πr=30°/360°×2×22/7×4.9×4.9
Solving it =12.57 cm² (approx)
Then distance travelled in a day=24×12.57
=301.68 cm² (approx)
So Distance travelled in a week=7×301.68
=2111.76 cm² (approx)
:) Hope this helps!!!!!!!!!!!!
Then in a clock each angle between two adjacent 5 min frequency is 30°
(as 12 sets of 5 min then 360°/12⇒30°)
Distance travelled in an hour = length of arc
Ф/360°×2πr=30°/360°×2×22/7×4.9×4.9
Solving it =12.57 cm² (approx)
Then distance travelled in a day=24×12.57
=301.68 cm² (approx)
So Distance travelled in a week=7×301.68
=2111.76 cm² (approx)
:) Hope this helps!!!!!!!!!!!!
nitthesh7:
if it was most helpful mark it as brainliest
Similar questions
Computer Science,
7 months ago
Science,
7 months ago
Geography,
7 months ago
Math,
1 year ago
English,
1 year ago