Question

the length of the hour hand of a clock is 4.9cm. Find the distance travelled by the tip of the hour hand in a week.

Answer 1

length of hour hand of clock=4.9cm(radius)
circumference of circle=2×pi×r
=2×22/7×4.9
=30.8cm
the hour hand moves two times a day from a point
distance. travel by the hour hand in one day=30.8×2
=61.6cm
distance travel by hour hand in a week=61.6×7

Answer 2

Radius = 4.9cm
Angle described by the minute hand in 12 hours = 360°
Therefore,
Angle described by the minute hand in 24 hours = 2×360 = 720°
Theta =720°
Area swept by the minute hand in 24 hours = πr²theta/360 = 22/7×4.9×4.9×720/360
= 150.29cm²
Area swept by the minute hand in one day = 150.29cm²
Area swept by the Minute hand in 7 days = 7×150.29 = 1056.44cm²