Question

The length of the hour hand of a clock is 6cm.find the area of sector swept by this hour hand in90 minutes

Answer 1

Answer:

Step-by-step explanation :   In 1 hour ( 60 minutes), the minute hand rotates 360°. Therefore, the area swept by the minute hand in 40 minutes will be the area of a sector of 240° in a circle of 6 cm radius. Area of sector of angle θ = (θ / 360°)x πr2 . Therefore, the area swept by the minute hand in 40 minutes is 75.42 cm2.

Answer 2

Answer:

Hope you will like my answer and mark it brainliest

Step-by-step explanation:

Let the hour hand s length be radius and clock be circle

so

r=6cm

the hand will cover full circle in 60 m

and a semi circle in remaining 30 m

so we have to find

area of circle +area of semi circle

πr^2+(πr^2)/2

(22/7*6*6)+(22/7*6*6)/2

=169.71cm^2