The length of the hypotenuse exceeds its base by 2 cm and exceeds 4 times its
longer side by
l cm . Find its sides
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Let the altitude of triangle be x cm.
Hypotenuse of triangle = 2x + 1
Base of triangle = 2x - 1.
According to the Question,
Using Pythagoras theorem,
⇒ (2x + 1)² = x² + (2x - 1)²
⇒ 4x² + 1 + 4x = x² + 4x² + 1 - 4x
⇒ x² - 8x = 0
⇒ x(x - 8) = 0
⇒ x = 0, 8 (Neglecting 0)
⇒ x = 8 cm
Altitude of triangle = x = 8 cm
Hypotenuse of triangle = 2x + 1 = 2(8) + 1 = 16 + 1 = 17 cm
Base of triangle = 2x - 1 = 2(18) - 1 = 16 - 1 = 15 cm.
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