The length of the hypotenuse of a right angled triangle exceeds length of its base by 1 cm and exceeds twice the length of the altitude by 3cm. Find the length of each side of the right angle. Please can you help me form the quadratic equation
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let the base be x
hypotaneos=x+1____;
let the altitude be y
hypotaneous=2y+3
now
x+1=2y+3
x-2y=3-1
x-2y=2_______
and
please ,solve the remaining part
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