the length of the hypotenuse of an isosceles right angle traingle is 4✓3m.then the length of one of its equal sides is
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answer is 2×[6]^(1/2) or simply [24]^(1/2)
by pythagoras theorem,
(hypotenuse )^2=(base)^2+(height )^2
here base=height
48=2x^2
x^2=24
x=[24]^(1/2)
ayan383729:
can't understand can you plz send me the solution
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