Question

The length of the largest pole that can be placed in the room of dimension 8m.6/ and 5m respectively is:- (a.) 5m (b.) 5underoot 5m (c.) 6m (d.) 125

Answer 1

Answer:

The length of the largest pole that

can be placed in the room is(b) 5√5 m

Step-by-step explanation:

GIVEN :

ROOM DIMENSION is 8m x 6m x 5 m.

TO FIND : The length of the largest pole

that can be placed in the room.

SOLUTION :

The room is off the form of a CUBOID.

A CUBOID has diagonals for all it's faces

and every diagonally opposite corner joins

to give BODY DIAGONAL.

The length of the largest pole that can

be placed in the room will be the

BODY DIAGONAL.

$BODY DIAGONAL \: = \: \sqrt{ {8}^{2} \times {6}^{2} \times {5}^{2} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \: \sqrt{64 + 36 + 25} \\ \\ \: BODY DIAGONAL = \sqrt{125} = \: 5\sqrt{5} m$

So, the BODY DIAGONAL = 11.1803 m

ANSWER : OPTION (B)

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