Question

the length of the largest pole that can be placed inside a tank of dimensions 12cm×10cm×5cm is

Answer 1

The length of the largest pole that can be placed inside the tank is of the length of its diagonal.
Therefore, the length of the pole=
$\sqrt{ {l}^{2} + {b}^{2} + {h}^{2} }$
it is given that, length of cuboid(l) =12cm
breadth of cuboid (b) = 10cm
height of cuboid (h)= 5cm
so, the length of the pole =
$\sqrt{ {12}^{2} + {10}^{2} + {5}^{2} }$
=
$\sqrt{144 + 100 + 25 }$
=$\sqrt{269}$
=16.4cm (approx.)