# The length of the lid of a steam chamber is 60 cm, its breadth is 5 cm and it is made up of a stone slab of thickness 1 cm. Some ice is kept on this slab. It is found that 5 kg of ice melts in 30 min. Determine the coefficient of thermal conductivity of the stone
assuming that no heat exchange occurs between the
stone and the atmosphere.
[Ans: 0.0074 CGS unit]
Answers
Answered by
1
Answer:
K=1.24J/m/s/
o
C
Explanation:
From Fourier's law we have,
dt
dQ
=
L
KA
(T
1
−T
2
)
Q=
L
KA
(T
1
−T
2
)t
Q=mL
f
L
KA
(T
1
−T
2
)t=mL
f
K=
A(T
1
−T
2
)t
mL
f
(L)
K=
0.36×100×3600
4.8×3.36×10
5
×0.1
J/m/s/
o
C
K=
0.36×36
4.8×3.36
K=1.24J/m/s/
o
C
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