Question

The length of the longest pole that can be placed on the floor of a room is 10 m and the length of the longest pole that can be placed in the room is 10 root 2 m. The height of the room is

Answer 1

Given:

Longest pole which can be placed on the floor = 10 m

Longest pole which can be placed in the room = 10_/2 m

To find:

Height of the room

Solution:

By the Pythagoras Theorem of Triangle, we know that:

Square of Hypotenuse is equal to the sum of squares of the other two sides.

According to the figure:

AB^2 = BC^2 + AC^2

=> AB^2 = (10)^2 + (10_/2)^2

=> AB^2 = 100 + 200

=> AB^2 = 300

=> AB = 10_/3 m

_______________

Answer 2

Solutions:

By the Pythagoras theorem.

AB² = BC² + AC²

AB² = (10)² + (10√2)²

AB² = 100 + 200

AB² = 300

AB = √300

AB = 10√3m

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