Question

The length of the longest rod that can be arranged in a cube of surface area 96sq.m

Answer 1

HEY!!

THE ANSWER IS HERE

Surface area= 96sq.m

$6 {s}^{2} = 96$

${s}^{2} = \frac{96}{6} = 16$

$s = 4m$

The longest rod that can be arranged in a cube is its diagnol.

Diagnol

$d = > \sqrt{3} s$

so the longest rod is

$= > 4 \sqrt{3} m$

:-)Hope it helps u.

Answer 2

surface area = 96sq.m
6a²=96
a²=96/6
a²=16
a=4m
the longest rod is a diagonal. so,
d=√3 a
d=4√3m