Question

the length of the longest rod that can be placed in a room of dimension 15 m× 12 m × 9 m is what​

Answer 1

That longest rod will be equal to the size of diagonal of the cuboidal room.

$\sqrt{ {15}^{2} + {12}^{2} + {9}^{2} } \\ \\ \implies \: \sqrt{225 + 144 + 81} \\ \\ \implies \: \sqrt{450 } = \: 21.213 \: {m}^{2} \: approx$

Answer 2

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Here, The longest rod will be equal to the size of diagonal of cuboidal room.

$= > \sqrt{ {15}^{2} + {12}^{2} + {9}^{2} }$

$= > \sqrt{225 + 144 + 81}$

$= > \sqrt{450}$

$= > 21.213 {m}^{2}$

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