Question

The length of the longest string in a piano is 2.0m and the wave velocity of
the string is 120 m/s. Find the frequencies of the first three harmonics.

Answer 1

Answer:

Hope it helps you

Explanation:

https://in.docworkspace.com/d/sIC-coOlPxc_XgQY

Answer 2

Answer:

30 Hz , 60 Hz, 90 Hz

Explanation:

Given,

The length of the longest string in a piano is 2.0m.

The wave velocity of the string is 120 m/s.

To find: the frequencies of the first three harmonics.

Solution:

Let the frequencies be f1,f2,f3 respectively.

we know, fN = Nv/ 2L

where, N is number of harmonic

and, v = wave velocity of string , L = length of longest string

f1 =  (1 * 120) / (2*2) = 30 Hz

f2 =  (2 * 120) / (2*2) = 60 Hz

f3 =  (3 * 120) / (2*2) = 90 Hz