The length of the major axis of the ellipse 16x² + 25y^2 = 400 is
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Step-by-step explanation:
ANSWER
For an ellipse of the form:
a
2
x
2
+
b
2
y
2
=1 (a>b>0)
Length of major axis: 2a
Length of minor axis: 2b
Eccentricity (e):
1−
a
2
b
2
Foci: (±ae,0)
Vertices: (±a,0)
Given ellipse:
16x
2
+25y
2
=400⟹
25
x
2
+
16
y
2
=1
Therefore, a=5,b=4
Now,
Length of major axis: 2a=10
Length of minor axis: 2b=8
Eccentricity (e):
1−
a
2
b
2
=
5
3
Foci: (±3,0)
Vertices: (±5,0)
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