Question

The length of the miniute hand of a clock is 20 cm find the area swept by the minuite hand in 10 min

Answer 1

Given :

• The length of the miniute hand of a clock is 20 cm

To find :

• the area swept by the minuite hand in 10 min

Solution :

Length of the minute hard of a clock

r = 20

Angle swept by minute hand in 10 minutes

Ø = 30°

Area swept by minute hand in 10 minutes

= Ø/360° x πr²

= 30/360° x 22/7 x 20 x 20

= 104.76 cm²

∴ the area swept by the minute hand in 10 min is 104.76 cm²

Answer 2

Answer:

✡ Given ✡

$\leadsto$ The length of the minute hand of a clock is 20 cm.

✡ To Find ✡

$\leadsto$ What is the area swept by the minute hand in 5 minutes.

✡ Solution ✡

✏ In 60 minutes, minute hand completes 360° i.e, one rotation.

$\Rightarrow$ In 1 minutes, minute hand completes,

$\implies$ $\dfrac{360°}{60}$ = 6°

Hence, in 10 minutes the angle covered is,

$\implies$ 6 × 5 = 30°

Then, the angle of sector formed is 30°

$\mapsto$ The area swept by the minute hand in 10 minutes,

$\implies$ $\dfrac{30}{360°}$ × π × 20 × 20

$\implies$ $\dfrac{30}{360°}$ × $\dfrac{22}{7}$ × 20 × 20

$\implies$ 104.76 cm²

$\therefore$ The area swept by the minute hand in 10 minutes is 104.76 cm².

Step-by-step explanation:

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