Question

the length of the minute hand is a clock is 14 cm . how much area will be swept by between 10:10AM to 10:30?​

Answer 1

Answer:

102.625 cm^2

Angle sweft by minute hand is 60° so u can use

((theta)/360 )* pi*r^2

you will get ur ans.

Answer 2

Answer:

• Area covered is 205.34 cm².

Step-by-step explanation:

Given that:

• Length of the minute hand of a clock is 14 cm.

To Find:

• Area covered by the hand clock between 10:10 am and 10:30 am.

As we know that:

• A clock is divided into 12 parts (i.e. numbering 1 - 12).
• Parts covered by the minute hand between 10:10 and 10:30 is 4 (i.e. 2 - 6)

So,

• Part of clock covered in between 10:10 to 10:30 = 4/12 = 1/3

Now,

Area of clock covered between 10:10 to 10:30 is :

$\sf{\longrightarrow\dfrac{1}{3}\times\pi r\:^2}$

Substituting the values,

$\sf\longrightarrow\dfrac{1}{3}\times\dfrac{22}{7} \times 14^2\\\\\longrightarrow\dfrac{1}{3}\times\dfrac{22}{7} \times 14\times14$

Reducing the numbers,

$\sf\longrightarrow\dfrac{1}{3}\times\dfrac{22}{1} \times 2\times14$

Multiplying the numbers,

$\sf\longrightarrow\dfrac{616}{3}$

Dividing the numbers,

$\sf\longrightarrow205.34$

Hence, area covered between 10:10 am to 10:30 am is 205.34 cm².