Question

The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand in 5 minutes​

Answer 1

Answer:

3080cm^2

Step-by-step explanation:

r=14cm;

area=pie * r^2

A=22/7*14*14

A=616cm^2

since it takes 5 full rotations and returns to the same point area will be-

5A = 5*616cm^2

final area= 3080cm^2

Answer 2

ANSWER:-

51.3cm³.

Given:

•The length of the minute hand of a clock is 14cm.

To find:

The area swept by the minute hand in 5 minutes.

Solution:

•The angle describe by the minute hand in 1 minute=66°

Therefore,

The angle described by 1minute hand in 5 minutes=30°.

Theta=30°

radius= 14cm

Now,

Area swept by the minute hand

$= > \pi {r}^{2} \times \frac{ \theta}{360 \degree} \\ \\ = > ( \frac{22}{7} \times 14 \times 14 \times \frac{30}{360} ) {cm}^{2} \\ \\ = >( 22 \times 2 \times 14 \times \frac{1}{12} ) {cm}^{2} \\ \\ = > \frac{308}{6} {cm}^{2} \\ \\ = > 51.33 {cm}^{2}$

Thus,

The area swept by the minute hand in 5 minutes is 51.33cm².

Thank you.