the length of the minute hand of a clock is 14 cm find the area swept by the minute hand in 5 minutes.
Answers
ANSWER
Minute hand completes full circle degree in 60 minutes.
Angle swept by minute in 60 minutes =360°
Angle swept by the minute hand in 15 minutes = 60°
360°
×15=90°
Therefore,
θ=90°
Length of minute hand =r=14cm
Area swept by minute hand in 15 minutes = Area of sector
As we know that area of sector is given as-
A=
360°
θ
×πr
2
Therefor,
Area swept by the minute hand in 15 minutes =
360°
90
×(
7
22
×(14)
2
)=
4
1
×616=154cm
2
Hence the area swept by the minute hand in 15 minutes is 154cm
2
.
Hence the correct answer is 154cm
2
.
Length of minute hand = radius of the clock (circle)
∴ Radius (r) of the circle = 14 cm (given)
Angle swept by minute hand in 60 minutes = 360°
So, the angle swept by the minute hand in 5 minutes = 360° × 5/60 = 30°
We know,
Area of a sector = (θ/360°) × πr2
Now, area of the sector making an angle of 30° = (30°/360°) × πr2 cm2
= (1/12) × π142
= (49/3)×(22/7) cm2
= 154/3 cm2