The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand in 5 minutes.
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area of the circle is 22/7*14*14=616
in 60 mins the minute hands covers 616 square cm
there fore in 5 mins it will cover =5*616/60=51.33 square cm
in 60 mins the minute hands covers 616 square cm
there fore in 5 mins it will cover =5*616/60=51.33 square cm
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Answer:
Step-by-step explanation:Area of circle =πr^2= 3.14*14*14 = 615.44
In 60 min, min hand covers angle =360°
In 5 min , min hand covers angle= (360÷60) * 5= 30°
Area of sector = (angle made by min hand * area of circle)÷360 = (30 * 615.44)÷360 = 51.28cm^2
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