The length of the minute hand of a clock is 42 cm. Find the area swept by the minute hand in 36 minutes.
(Leave your answer as a fraction where necessary.)
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Answer:
In 60 minutes the large hand (minute hand) covers goes one round (=360°).
So in 20 minutes it makes 120° = 2π/3 radians.
The formula for the length of curve is l = r θ = 42 (2π/3) = 14 (44/7) = 88 cms.
Hence the extremity of the minute hand moves 88 cm.
Step-by-step explanation:
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Answer:
length of the minute hand of the clock will be the radius of the circle. So, radius r = 42cm
Angle swept by the clock hand in 1 min = (360/60)° = 6° per minute
Angle swept by the clock in 36 mins = (6×36)° = 216°
Area of the circle = π(r^2) [ 360°]
So, Area of the circle swept by the minute hand in 36 minutes = [π(r^2)×216] / 360 = 3323.37 cm^2 (3.323 m^2)
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