The length of the minute hand of a clock is 5 cm find the area from 7:10 to 7 :45
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Solution,
60 min= 360°
So, 1 min.= 360°/60= 6°
=> Angle between 7:10 to 7:45 = 6* 35= 210°
Area coverd= 22/7 * 210 * 25/ 360°
= 45.8 cm* cm.
60 min= 360°
So, 1 min.= 360°/60= 6°
=> Angle between 7:10 to 7:45 = 6* 35= 210°
Area coverd= 22/7 * 210 * 25/ 360°
= 45.8 cm* cm.
Answered by
0
Hey Jude here is your kind answer.
As we all know that a minute hand cover 30° in 5 mins.
So, it will cover 210° in between 7:10 to 7:45 because, it covers 7 x 30°.
Now, as per the question we have radius of the clock =5 cm
So , area swept by minute hand will be :-
(210 / 360) x πr²
=> 210 / 360 x 22 / 7 x 5 x 5
=> 7 / 12 x 22 / 7 x 5 x 5
=> 45.83 cm²
Thanking you, for your kind question ;if it helps you and if you are agreed by my answer mark it brainliest please .
As we all know that a minute hand cover 30° in 5 mins.
So, it will cover 210° in between 7:10 to 7:45 because, it covers 7 x 30°.
Now, as per the question we have radius of the clock =5 cm
So , area swept by minute hand will be :-
(210 / 360) x πr²
=> 210 / 360 x 22 / 7 x 5 x 5
=> 7 / 12 x 22 / 7 x 5 x 5
=> 45.83 cm²
Thanking you, for your kind question ;if it helps you and if you are agreed by my answer mark it brainliest please .
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