the length of the minute hand of a clock is 5 cm find the area swept by the minute hand during the time from 4:5 a.m. to 4:40 a.m.
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Let's see the angle swept by minute hand....
In 60 min. it sweeps 360°.
So, in 1 min 6°
Thus, from 4:05 to 4:40,
It will sweep an angle of 35*6 = 210°.....
Now, area swept
= (Angle/360) * π * r^2
= (210/360) * 22/7 * 25
= 275/6
= 45.83 cm^2....
In 60 min. it sweeps 360°.
So, in 1 min 6°
Thus, from 4:05 to 4:40,
It will sweep an angle of 35*6 = 210°.....
Now, area swept
= (Angle/360) * π * r^2
= (210/360) * 22/7 * 25
= 275/6
= 45.83 cm^2....
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