The length of the minute hand of a clock is 5 cm. Find the area swept by the
minute hand during the time period 6:05 am to 6:40 am
Answers
Answered by
4
total minutes = 30 + 5 = 35
1min=6°
45min = 6 * 35
= 210°
area of the sector = 210°/360 * 22/7 *5 * 5
= 7/9 * 22/7 * 5 * 5
= 19.5 (22/7)
1min=6°
45min = 6 * 35
= 210°
area of the sector = 210°/360 * 22/7 *5 * 5
= 7/9 * 22/7 * 5 * 5
= 19.5 (22/7)
Somanna555:
the answer is approx 45.88
Answered by
6
Watch means Circle
Area of Sector = θ /360 ×πr^2
here θ =210°
(5 minutes =30° ,so 35 minute = 210°)
r= 5cm
π=22/7
so Area swept = 210/360 × 22/7 ×5×5
= 7/12 ×22/7 ×25
=11/6×25
= 275/6 sqcm or 45.83 sqcm
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