The length of the minute hand of a clock is 6cm . Find the area swept by the minute hand during the time period 8:05 AM and 8:45 AM.
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Answered by
3
radius of sector=6 cm
/alpha=240 degree
area of sector=/alpha/360*/pi*r^2
area of sector= 240/360*22/7*6*6
=75.42. ans...........
/alpha=240 degree
area of sector=/alpha/360*/pi*r^2
area of sector= 240/360*22/7*6*6
=75.42. ans...........
Anonymous:
angle swept in 5 min.. is 30 degree so in 40 min...it will be 240 degree
radius is 6 cm
now apply the form
formula of area of sector
you are mising one 6
pie r square hota hai
ha yrr......sry r square hoga
edit it
now it's crct
yes
Answered by
5
area of the sector=πr²*x/360
x=angle
=240·
r=6 cm
area of the sector=22/7*36*2/3=75.4...cm²
x=angle
=240·
r=6 cm
area of the sector=22/7*36*2/3=75.4...cm²
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