the length of the miute hand of a clock is 5cm .find the area swept by the minute hand during the time period 6.05am and 6.40am
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length of minute hand = 5 cm
time period is 6:05 and 6:40
time is 40 -5 =35
minute hand moves in 60 min then angle will be 360°
if it moves in 1 min then = 360 /60
in 1 min the minute hand makes angle = 6°
in 35 mins = 6 *35
210 °
area minute hand cover in 6 :05 to 6:40 =
Ф/360 * πr²
210 * 22 * 5 * 5 / 360 * 7
= 275 / 6
45 .83 cm²
time period is 6:05 and 6:40
time is 40 -5 =35
minute hand moves in 60 min then angle will be 360°
if it moves in 1 min then = 360 /60
in 1 min the minute hand makes angle = 6°
in 35 mins = 6 *35
210 °
area minute hand cover in 6 :05 to 6:40 =
Ф/360 * πr²
210 * 22 * 5 * 5 / 360 * 7
= 275 / 6
45 .83 cm²
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