Question

the length of the miute hand of a clock is 5cm .find the area swept by the minute hand during the time period 6.05am and 6.40am

Answer 1

length of minute hand = 5 cm
time period is  6:05 and 6:40
time is  40 -5 =35 

minute hand moves in 60 min then angle will be 360°
if it moves in 1 min then = 360 /60
in 1 min the minute hand  makes angle = 6°
in 35 mins = 6 *35 
210 °

area minute hand cover in 6 :05 to 6:40 =
Ф/360 * πr²
210 * 22 * 5 * 5 / 360 * 7
= 275 / 6 
45 .83 cm²