the length of the parallel side of the trapezium is 12 cm and 8 cm .the distance between them is 4 cm .the area of the trapezium will be
Answers
Answer:
6
Step-by-step explanation:
Area formula for a trapezium (a.k.a trapezoid):
A=b1+b22h
Where A is the total area, b1 and b2 are the parallell sides of the trapezoid, and h is the height of the trapezoid. And we want to know what? Right, the height, or h . So, let’s rewrite the formula:
A=b1+b22h
2A=(b1+b2)h
2Ab1+b2=h
Now let us look at what is known:
A=30
b1=4
b2=8
Finally, insert the numbers:
2⋅304+8=6012=5
Answer: h=5
There you go. Everything you need to solve your particular problem. Now solve it! :)
Let the parallel sides of trapezium be 'a' and 'b' and the distance between them i.e. the height of trapezium be 'h'.
Therefore area of trapezium is given by
=1/2 *(sum of parallel side)*(distance between parallel side i.e. height of trapezium) ……(1)
Now take 'a'=12 & 'b'=8 …. (Sides are given)
Therefore,
Sum of parallel sides=a+b=12+8…. (2)
Sum of parallel side=20cm
Area=60 cm^2 …..(given) …..(3)
Putting (2) & (3) in (1) we get,
60=1/2 * 20*h
h=60/10
h=6cm
Therefore height of trapezium is 6cm.
Answer:
length if parallel sides
a=12cm
b=8cm
height=4cm
The area of trapezium=1/2×(sum of parallel sides)×height
=1/2×(12+8)×4
; =20×2=40cm²