Question

The length of the parallel sides of a trapezium are 34 cm and 16cm and its area is 250cm². The distance between the parallel sides is​

Answer 1

The formula for trapezium is

$\color{pink} \frac{1}{2} h(a + b)$

so,

$\frac{1}{2} h(34+ 16) \: = 250$

50h=250×2

50h=500

h=500/50

h=10

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Answer 2

Question :-

The length of the parallel sides of a trapezium are 34 cm and 16cm and its area is 250cm². What's distance between the parallel sides?

Given :-

▪The length of the parallel sides of a trapezium are 34 cm and 16cm.

▪ Area of trapezium = 250 cm²

To Find :-

▪ Distance between the parallel sides (h)

Solution :-

Let's the parallel sides be x ( 34 cm) and y ( 16 cm)

We know,

★ ${\underline{\boxed{\bf{\blue{Area_{(trapezium)} = \dfrac{1}{2} \times (sum\;of\;it\; parallel\;sides) \times height}}}}}$

Now, put the given values

⟹ 250 = ½ × (x+y) × h

⟹ 250 = ½ × ( 34 +16) ×h

⟹ 250 = 25 h

⟹ h = 10 cm

$:\implies{\underline{\boxed{\bf{\blue{h = 10\;cm}}}}}$

Hence,

the distance between the parallel sides is = 10 cm.