the length of the parallel sides of a Trapezium are in the ratio 3 is to 5 and the distance between them is 10 cm if the area of a Trapezium is 120 CM square find the length of its parallel sides
Answers
Answered by
13
Heya!
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♦Let the sides of the Trapezium be 3x and 5x respectively !
♦Area of Trapezium=> ½ ( b1 + b2 ) × H
Therefore ,
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120 = ½ ( 3x + 5x ) × 10
120 = 5(8x)
120 = 40x
x=>> 3
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↪Length of the parallel sides are 3(3) = 9cm and 3(5) = 15 cm !!
------------------------------------------------------------------------------------------------
--------
=============================================================
♦Let the sides of the Trapezium be 3x and 5x respectively !
♦Area of Trapezium=> ½ ( b1 + b2 ) × H
Therefore ,
--------------
120 = ½ ( 3x + 5x ) × 10
120 = 5(8x)
120 = 40x
x=>> 3
======
↪Length of the parallel sides are 3(3) = 9cm and 3(5) = 15 cm !!
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Answered by
4
Hey Friends,
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Let the parallel side be 3x & 5x.
Hight=10 cm.
Area of Trapezium = 1/2(3x+5x)×10
120=8x/2×10
120=40x
x=3
Parallel side are 3×3=9 cm & 5×3=15 cm.
HOPE IT'S HELP YOU!!!!!!
______________________________
______________________________
Let the parallel side be 3x & 5x.
Hight=10 cm.
Area of Trapezium = 1/2(3x+5x)×10
120=8x/2×10
120=40x
x=3
Parallel side are 3×3=9 cm & 5×3=15 cm.
HOPE IT'S HELP YOU!!!!!!
______________________________
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