The length of the parallel sides of a trapezium are (x +3) cm and (x +9) cm. Given also that the height of the trapezium is (3x – 4) cm and that it has an area of 80 cm2, find the value of x.
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Step-by-step explanation:
area of a trapezium=(h/2)(a+b)
80=(3x-4)(2x+12)/2
160=6x^2+36x-8x-48
160=6x^2+28x-48
6x^2+28x-208=0
1248=2*624=2*2*312=2*2*2*156=2*2*2*2*78=2*2*2*2*2*39=2*2*2*2*2*13*3
24,52
6x^2-24x+52x-208=0
6x(x-4)+52(x-4)=0
x=4
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