Question

the length of the parallel sides of a Trapezium are (x+9)cm and (2x-3)cm and the distance between them is (x+4)cm. if its area is 540 cm sq. ,find x​

Answer 1

Answer:

Step-by-step explanation:

We know that

Area of trap.=1/2×sum of parallel sides ×height

540= 1/2×(x+9+2x-3)×(x+4)

= 1/2×(3x+6)×(x+4)

= 1/2×(3x^2+12x+6x+24)

540×2=3x^2 +18x+24

1080-24=3x^2+18x

1056=3x^2+18x

or, 3x^2+18x-1056=0

3(x^2+6x-352)=0

x^2+6x-352=0

Now, By splitting middle term method, we get--

x^2+22x-16x-352=0

x(x+22)-16(x+22)=0

(x-16)(x+22)=0

So, x=16, -22

Thanks !!!!