the length of the parallel sides of an isosceles trapezium are 6 cm and 14 cm the length of non parallel sides is same ,i.e., 5 cm find the area of the trapezium
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As AE is the perpendicular distance so base equals to square of hypotenuse minus square of perpendicular
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aftab172:
bro answer 30 sq. cm aaraha hai you are wrong
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it is a pythogorean theorem question .
longer side = 14
shorter side = 6
a trap. has two right triangle in both the ends
so we can put pythogorean theorem
first difference between them
and divid it to get a base of one triangle
14-6=8
8/2
5²-4²=3²( pythogorean theorem)
so it is like a simple
area of a trapezium = 1/2×hieght × sum of parallel sides
now we have found the h by pythogorean theorem
h= 3
1/2×3×20=30 cm²
longer side = 14
shorter side = 6
a trap. has two right triangle in both the ends
so we can put pythogorean theorem
first difference between them
and divid it to get a base of one triangle
14-6=8
8/2
5²-4²=3²( pythogorean theorem)
so it is like a simple
area of a trapezium = 1/2×hieght × sum of parallel sides
now we have found the h by pythogorean theorem
h= 3
1/2×3×20=30 cm²
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