Question

The length of the pendulum is doubled and the mass of its bob is halved. Its time period would

Answer 1

Answer:

when the length is doubled then,

$t = 2\pi \sqrt{ \frac{l}{g} }$

as length is doubled so,

$t = 2\pi \sqrt{ \frac{2l}{g} }$

so there is an increase in the time period by the factor of √2

$t = \sqrt{2} \: \: (2\pi \sqrt{ \frac{l}{g} } )$

where the mass is concerned, the time period of the pendulum is independent of mass of the Bob. Hence, it will not affect the time period.