The length of the perpendicular segment from the origin to a line is 2 units
and the inclination of this perpendicular is a such that sin a=1/3 where a is acute
acute. Find the equation of the line.
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y = - 2√2x + 6 perpendicular from the origin to the line is inclined at a such that sin a=1/3 and length = 2 unit
Step-by-step explanation:
Sina = 1/3
=> 1/3 = Perpendicular / hypotenuse
=> 1/3 = P/2
=> P = 2/3
Base = √2² - (2/3)² = √ 4 - 4/9 = 4√2/3
Hence coordinate of perpendicular segment Touching line
= ( 4√2/3 , 2/3)
Slope of Perpendicular
= (2/3)/(4√2/3)
= 1/2√2
Slope of line = -1/1/2√2 = - 2√2
Equation of line
y = - 2√2x + c
point ( 4√2/3 , 2/3)
=> 2/3 = - 2√2 * 4√2/3 + c
=> 2/3 = -16/3 + c
=> c = 18/3
=> c = 6
y = - 2√2x + 6 is Equation of line
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