The length of the radius of a circle with it's center o is 5cm and the length of it's chord ab is 8cm let us write by calculating the distance of the chord ab from the center O
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The length of the radius of a circle with it's center o is 5cm and the length of it's chord ab is 8cm let us write by calculating the distance of the chord ab from the center O
Step-by-step explanation:
radius = 5cm, AB = 5cm
Any chord bisects the circle into two perpendicular from the center of the circle.
∴, AD = BD
In ∠ODB
OB = 5cm
BD = 4cm
When we use Pythagoras Theorem:
base² + Height² = hypotenuse²
OD² + DB² = OB²
OD² = 25-16
OD²= 9
OD = 3cm
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